12z/5-52=20-2z/5

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Solution for 12z/5-52=20-2z/5 equation: 



12z/5-52=20-2z/5

We move all terms to the left:

12z/5-52-(20-2z/5)=0

We add all the numbers together, and all the variables

12z/5-(-2z/5+20)-52=0

We get rid of parentheses

12z/5+2z/5-20-52=0

We multiply all the terms by the denominator


12z+2z-20*5-52*5=0

We add all the numbers together, and all the variables

14z-360=0

We move all terms containing z to the left, all other terms to the right

14z=360

z=360/14

z=25+5/7

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