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=A(4A+6)
We move all terms to the left:
-(A(4A+6))=0
We calculate terms in parentheses: -(A(4A+6)), so:We get rid of parentheses
A(4A+6)
We multiply parentheses
4A^2+6A
Back to the equation:
-(4A^2+6A)
-4A^2-6A=0
a = -4; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·(-4)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*-4}=\frac{0}{-8} =0 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*-4}=\frac{12}{-8} =-1+1/2 $
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