7+(5+6x)=(8x-3)+8x

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Solution for 7+(5+6x)=(8x-3)+8x equation: 



7+(5+6x)=(8x-3)+8x

We move all terms to the left:

7+(5+6x)-((8x-3)+8x)=0

We add all the numbers together, and all the variables

(6x+5)-((8x-3)+8x)+7=0

We get rid of parentheses

6x-((8x-3)+8x)+5+7=0



We calculate terms in parentheses: -((8x-3)+8x), so:

(8x-3)+8x

We add all the numbers together, and all the variables

8x+(8x-3)

We get rid of parentheses

8x+8x-3

We add all the numbers together, and all the variables

16x-3

Back to the equation:

-(16x-3)



We add all the numbers together, and all the variables

6x-(16x-3)+12=0

We get rid of parentheses

6x-16x+3+12=0

We add all the numbers together, and all the variables

-10x+15=0

We move all terms containing x to the left, all other terms to the right

-10x=-15

x=-15/-10

x=1+1/2

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