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=5A(7+9A)
We move all terms to the left:
-(5A(7+9A))=0
We add all the numbers together, and all the variables
-(5A(9A+7))=0
We calculate terms in parentheses: -(5A(9A+7)), so:We get rid of parentheses
5A(9A+7)
We multiply parentheses
45A^2+35A
Back to the equation:
-(45A^2+35A)
-45A^2-35A=0
a = -45; b = -35; c = 0;
Δ = b2-4ac
Δ = -352-4·(-45)·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-35}{2*-45}=\frac{0}{-90} =0 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+35}{2*-45}=\frac{70}{-90} =-7/9 $
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