1/3(x+5)+x=4(x-4)-9

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Solution for 1/3(x+5)+x=4(x-4)-9 equation: 



1/3(x+5)+x=4(x-4)-9

We move all terms to the left:

1/3(x+5)+x-(4(x-4)-9)=0



Domain of the equation: 3(x+5)!=0

x∈R



We add all the numbers together, and all the variables

x+1/3(x+5)-(4(x-4)-9)=0

We multiply all the terms by the denominator


x*3(x+5)-((4(x-4)-9))*3(x+5)+1=0



We calculate terms in parentheses: -((4(x-4)-9))*3(x+5), so:

(4(x-4)-9))*3(x+5



Wy multiply elements

3x^2(x-((4(x-4)-9))*3(x+5)+1=0

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