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=5A(A-2)
We move all terms to the left:
-(5A(A-2))=0
We calculate terms in parentheses: -(5A(A-2)), so:We get rid of parentheses
5A(A-2)
We multiply parentheses
5A^2-10A
Back to the equation:
-(5A^2-10A)
-5A^2+10A=0
a = -5; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-5)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-5}=\frac{-20}{-10} =+2 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-5}=\frac{0}{-10} =0 $
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