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=1/2A(A+6+2A-3)
We move all terms to the left:
-(1/2A(A+6+2A-3))=0
Domain of the equation: 2A(A+6+2A-3))!=0We add all the numbers together, and all the variables
A∈R
-(1/2A(3A+3))=0
We multiply all the terms by the denominator
-(1=0
We add all the numbers together, and all the variables
=0
A=0/1
A=0
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