4(s+3)=2-(-4s-10)

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Solution for 4(s+3)=2-(-4s-10) equation: 



4(s+3)=2-(-4s-10)

We move all terms to the left:

4(s+3)-(2-(-4s-10))=0

We multiply parentheses

4s-(2-(-4s-10))+12=0



We calculate terms in parentheses: -(2-(-4s-10)), so:

2-(-4s-10)

determiningTheFunctionDomain
-(-4s-10)+2

We get rid of parentheses

4s+10+2

We add all the numbers together, and all the variables

4s+12

Back to the equation:

-(4s+12)



We get rid of parentheses

4s-4s-12+12=0

We add all the numbers together, and all the variables

=0

s=0/1

s=0

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