A=(5x-5)+19-x

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Solution for A=(5x-5)+19-x equation:



=(5A-5)+19-A
We move all terms to the left:
-((5A-5)+19-A)=0
We calculate terms in parentheses: -((5A-5)+19-A), so:
(5A-5)+19-A
determiningTheFunctionDomain (5A-5)-A+19
We add all the numbers together, and all the variables
-1A+(5A-5)+19
We get rid of parentheses
-1A+5A-5+19
We add all the numbers together, and all the variables
4A+14
Back to the equation:
-(4A+14)
We get rid of parentheses
-4A-14=0
We move all terms containing A to the left, all other terms to the right
-4A=14
A=14/-4
A=-3+1/2

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