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7y^2-11/3y-2/3=0
Domain of the equation: 3y!=0We calculate fractions
y!=0/3
y!=0
y∈R
7y^2=0
a = 7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·7·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{0}{14}=0$
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