A/8-2(2a-5)=2(a+3)-3a

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Solution for A/8-2(2a-5)=2(a+3)-3a equation: 



/8-2(2A-5)=2(A+3)-3A

We move all terms to the left:

/8-2(2A-5)-(2(A+3)-3A)=0

We multiply parentheses

-4A-(2(A+3)-3A)+10+/8=0

We multiply all the terms by the denominator


-4A*8-((2(A+3)-3A))*8+10*8+=0

We add all the numbers together, and all the variables

-4A*8-((2(A+3)-3A))*8=0

Wy multiply elements

-32A-((2(A+3)-3A))*8=0

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