1/2(n+2)=1/3(2n+4)

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Solution for 1/2(n+2)=1/3(2n+4) equation: 



1/2(n+2)=1/3(2n+4)

We move all terms to the left:

1/2(n+2)-(1/3(2n+4))=0



Domain of the equation: 2(n+2)!=0

n∈R





Domain of the equation: 3(2n+4))!=0

n∈R



We calculate fractions


(3n2/(2(n+2)*3(2n+4)))+(-2nn/(2(n+2)*3(2n+4)))=0



We calculate terms in parentheses: +(3n2/(2(n+2)*3(2n+4))), so:

3n2/(2(n+2)*3(2n+4))

We multiply all the terms by the denominator


3n2

We add all the numbers together, and all the variables

3n^2

Back to the equation:

+(3n^2)





We calculate terms in parentheses: +(-2nn/(2(n+2)*3(2n+4))), so:

-2nn/(2(n+2)*3(2n+4))

We multiply all the terms by the denominator


-2nn

Back to the equation:

+(-2nn)



We get rid of parentheses

3n^2-2nn=0

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