A(n)=1+(n-1)(6)

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Solution for A(n)=1+(n-1)(6) equation: 



(A)=1+(A-1)(6)

We move all terms to the left:

(A)-(1+(A-1)(6))=0



We calculate terms in parentheses: -(1+(A-1)6), so:

1+(A-1)6

determiningTheFunctionDomain
(A-1)6+1

We multiply parentheses

6A-6+1

We add all the numbers together, and all the variables

6A-5

Back to the equation:

-(6A-5)



We get rid of parentheses

A-6A+5=0

We add all the numbers together, and all the variables

-5A+5=0

We move all terms containing A to the left, all other terms to the right

-5A=-5

A=-5/-5

A=1

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