18y-6y=11(y+2)-y

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Solution for 18y-6y=11(y+2)-y equation: 



18y-6y=11(y+2)-y

We move all terms to the left:

18y-6y-(11(y+2)-y)=0

We add all the numbers together, and all the variables

12y-(11(y+2)-y)=0



We calculate terms in parentheses: -(11(y+2)-y), so:

11(y+2)-y

We add all the numbers together, and all the variables

-1y+11(y+2)

We multiply parentheses

-1y+11y+22

We add all the numbers together, and all the variables

10y+22

Back to the equation:

-(10y+22)



We get rid of parentheses

12y-10y-22=0

We add all the numbers together, and all the variables

2y-22=0

We move all terms containing y to the left, all other terms to the right

2y=22

y=22/2

y=11

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