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(A)=-6+(A-1(1/6)
We move all terms to the left:
(A)-(-6+(A-1(1/6))=0
We add all the numbers together, and all the variables
A-(-6+(A-1(+1/6))=0
We multiply all the terms by the denominator
A*6))-(-6+(A-1(+1=0
We add all the numbers together, and all the variables
A*6))-(-6+(A=0
Wy multiply elements
6A^2=0
a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$A=\frac{-b}{2a}=\frac{0}{12}=0$
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