(z)+(4/z+1)=3

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Solution for (z)+(4/z+1)=3 equation: 



(z)+(4/z+1)=3

We move all terms to the left:

(z)+(4/z+1)-(3)=0



Domain of the equation: z+1)!=0

z∈R



We get rid of parentheses

z+4/z+1-3=0

We multiply all the terms by the denominator


z*z+1*z-3*z+4=0

We add all the numbers together, and all the variables

-2z+z*z+4=0

Wy multiply elements

z^2-2z+4=0

a = 1; b = -2; c = +4;
Δ = b2-4ac
Δ = -22-4·1·4
Δ = -12
Delta is less than zero, so there is no solution for the equation

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