3(x-20)+4x=6(x+5)

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Solution for 3(x-20)+4x=6(x+5) equation: 



3(x-20)+4x=6(x+5)

We move all terms to the left:

3(x-20)+4x-(6(x+5))=0

We add all the numbers together, and all the variables

4x+3(x-20)-(6(x+5))=0

We multiply parentheses

4x+3x-(6(x+5))-60=0



We calculate terms in parentheses: -(6(x+5)), so:

6(x+5)

We multiply parentheses

6x+30

Back to the equation:

-(6x+30)



We add all the numbers together, and all the variables

7x-(6x+30)-60=0

We get rid of parentheses

7x-6x-30-60=0

We add all the numbers together, and all the variables

x-90=0

We move all terms containing x to the left, all other terms to the right

x=90

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