=(2y+1)(2y-1)

Solution for =(2y+1)(2y-1) equation:

Simplifying
0 = (2y + 1)(2y + -1)

Reorder the terms:
0 = (1 + 2y)(2y + -1)

Reorder the terms:
0 = (1 + 2y)(-1 + 2y)

Multiply (1 + 2y) * (-1 + 2y)
0 = (1(-1 + 2y) + 2y * (-1 + 2y))
0 = ((-1 * 1 + 2y * 1) + 2y * (-1 + 2y))
0 = ((-1 + 2y) + 2y * (-1 + 2y))
0 = (-1 + 2y + (-1 * 2y + 2y * 2y))
0 = (-1 + 2y + (-2y + 4y2))

Combine like terms: 2y + -2y = 0
0 = (-1 + 0 + 4y2)
0 = (-1 + 4y2)

Solving
0 = -1 + 4y2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y2' to each side of the equation.
0 + -4y2 = -1 + 4y2 + -4y2
Remove the zero:
-4y2 = -1 + 4y2 + -4y2

Combine like terms: 4y2 + -4y2 = 0
-4y2 = -1 + 0
-4y2 = -1

Divide each side by '-4'.
y2 = 0.25

Simplifying
y2 = 0.25

Take the square root of each side:
y = {-0.5, 0.5}