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9z^2-52z+75=0
a = 9; b = -52; c = +75;
Δ = b2-4ac
Δ = -522-4·9·75
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-2}{2*9}=\frac{50}{18} =2+7/9 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+2}{2*9}=\frac{54}{18} =3 $
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