2z-26=4z-80

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Solution for 2z-26=4z-80 equation: 



2z-26=4z-80

We move all terms to the left:

2z-26-(4z-80)=0

We get rid of parentheses

2z-4z+80-26=0

We add all the numbers together, and all the variables

-2z+54=0

We move all terms containing z to the left, all other terms to the right

-2z=-54

z=-54/-2

z=+27

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