9y+7-2(-4y-3)=3(y-1)

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Solution for 9y+7-2(-4y-3)=3(y-1) equation: 



9y+7-2(-4y-3)=3(y-1)

We move all terms to the left:

9y+7-2(-4y-3)-(3(y-1))=0

We multiply parentheses

9y+8y-(3(y-1))+6+7=0



We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We add all the numbers together, and all the variables

17y-(3y-3)+13=0

We get rid of parentheses

17y-3y+3+13=0

We add all the numbers together, and all the variables

14y+16=0

We move all terms containing y to the left, all other terms to the right

14y=-16

y=-16/14

y=-1+1/7

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