5(y-3)-3=-3(-9y+4)-6y

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Solution for 5(y-3)-3=-3(-9y+4)-6y equation: 



5(y-3)-3=-3(-9y+4)-6y

We move all terms to the left:

5(y-3)-3-(-3(-9y+4)-6y)=0

We multiply parentheses

5y-(-3(-9y+4)-6y)-15-3=0



We calculate terms in parentheses: -(-3(-9y+4)-6y), so:

-3(-9y+4)-6y

We add all the numbers together, and all the variables

-6y-3(-9y+4)

We multiply parentheses

-6y+27y-12

We add all the numbers together, and all the variables

21y-12

Back to the equation:

-(21y-12)



We add all the numbers together, and all the variables

5y-(21y-12)-18=0

We get rid of parentheses

5y-21y+12-18=0

We add all the numbers together, and all the variables

-16y-6=0

We move all terms containing y to the left, all other terms to the right

-16y=6

y=6/-16

y=-3/8

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