9y+33=3(y+7)

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Solution for 9y+33=3(y+7) equation: 



9y+33=3(y+7)

We move all terms to the left:

9y+33-(3(y+7))=0



We calculate terms in parentheses: -(3(y+7)), so:

3(y+7)

We multiply parentheses

3y+21

Back to the equation:

-(3y+21)



We get rid of parentheses

9y-3y-21+33=0

We add all the numbers together, and all the variables

6y+12=0

We move all terms containing y to the left, all other terms to the right

6y=-12

y=-12/6

y=-2

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