(1/6)x+(2/3)x+4=x+2

Solution for (1/6)x+(2/3)x+4=x+2 equation:

(1/6)x+(2/3)x+4=x+2

We move all terms to the left:

(1/6)x+(2/3)x+4-(x+2)=0


Domain of the equation: 6)x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/6)x+(+2/3)x-(x+2)+4=0

We multiply parentheses

x^2+2x^2-(x+2)+4=0

We get rid of parentheses

x^2+2x^2-x-2+4=0

We add all the numbers together, and all the variables

3x^2-1x+2=0

a = 3; b = -1; c = +2;
Δ = b2-4ac
Δ = -12-4·3·2
Δ = -23
Delta is less than zero, so there is no solution for the equation