9y+3(y-6)=20

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Solution for 9y+3(y-6)=20 equation: 



9y+3(y-6)=20

We move all terms to the left:

9y+3(y-6)-(20)=0

We multiply parentheses

9y+3y-18-20=0

We add all the numbers together, and all the variables

12y-38=0

We move all terms containing y to the left, all other terms to the right

12y=38

y=38/12

y=3+1/6

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