6(x-3)+5=4(x+2)+3

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Solution for 6(x-3)+5=4(x+2)+3 equation: 



6(x-3)+5=4(x+2)+3

We move all terms to the left:

6(x-3)+5-(4(x+2)+3)=0

We multiply parentheses

6x-(4(x+2)+3)-18+5=0



We calculate terms in parentheses: -(4(x+2)+3), so:

4(x+2)+3

We multiply parentheses

4x+8+3

We add all the numbers together, and all the variables

4x+11

Back to the equation:

-(4x+11)



We add all the numbers together, and all the variables

6x-(4x+11)-13=0

We get rid of parentheses

6x-4x-11-13=0

We add all the numbers together, and all the variables

2x-24=0

We move all terms containing x to the left, all other terms to the right

2x=24

x=24/2

x=12

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