9y+20=2(y+3)

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Solution for 9y+20=2(y+3) equation: 



9y+20=2(y+3)

We move all terms to the left:

9y+20-(2(y+3))=0



We calculate terms in parentheses: -(2(y+3)), so:

2(y+3)

We multiply parentheses

2y+6

Back to the equation:

-(2y+6)



We get rid of parentheses

9y-2y-6+20=0

We add all the numbers together, and all the variables

7y+14=0

We move all terms containing y to the left, all other terms to the right

7y=-14

y=-14/7

y=-2

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