28*m*m+18*m=0

Solution for 28*m*m+18*m=0 equation:

28m*m+18m=0

We add all the numbers together, and all the variables

18m+28m*m=0

Wy multiply elements

28m^2+18m=0

a = 28; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·28·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*28}=\frac{-36}{56}
=-9/14
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*28}=\frac{0}{56}
=0
$