9y+1-4(-3y-1)=3(y-1)

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Solution for 9y+1-4(-3y-1)=3(y-1) equation: 



9y+1-4(-3y-1)=3(y-1)

We move all terms to the left:

9y+1-4(-3y-1)-(3(y-1))=0

We multiply parentheses

9y+12y-(3(y-1))+4+1=0



We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We add all the numbers together, and all the variables

21y-(3y-3)+5=0

We get rid of parentheses

21y-3y+3+5=0

We add all the numbers together, and all the variables

18y+8=0

We move all terms containing y to the left, all other terms to the right

18y=-8

y=-8/18

y=-4/9

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