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1/4(x+3)=1/2(x+2)
We move all terms to the left:
1/4(x+3)-(1/2(x+2))=0
Domain of the equation: 4(x+3)!=0
x∈R
Domain of the equation: 2(x+2))!=0We calculate fractions
x∈R
(2xx/(4(x+3)*2(x+2)))+(-4xx/(4(x+3)*2(x+2)))=0
We calculate terms in parentheses: +(2xx/(4(x+3)*2(x+2))), so:
2xx/(4(x+3)*2(x+2))
We multiply all the terms by the denominator
2xx
Back to the equation:
+(2xx)
We calculate terms in parentheses: +(-4xx/(4(x+3)*2(x+2))), so:We get rid of parentheses
-4xx/(4(x+3)*2(x+2))
We multiply all the terms by the denominator
-4xx
Back to the equation:
+(-4xx)
2xx-4xx=0
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