16x-12=4(2x-3)+8x

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Solution for 16x-12=4(2x-3)+8x equation: 



16x-12=4(2x-3)+8x

We move all terms to the left:

16x-12-(4(2x-3)+8x)=0



We calculate terms in parentheses: -(4(2x-3)+8x), so:

4(2x-3)+8x

We add all the numbers together, and all the variables

8x+4(2x-3)

We multiply parentheses

8x+8x-12

We add all the numbers together, and all the variables

16x-12

Back to the equation:

-(16x-12)



We get rid of parentheses

16x-16x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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