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9x^2=96x
We move all terms to the left:
9x^2-(96x)=0
a = 9; b = -96; c = 0;
Δ = b2-4ac
Δ = -962-4·9·0
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-96}{2*9}=\frac{0}{18} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+96}{2*9}=\frac{192}{18} =10+2/3 $
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