9x2-48=18x

Solution for 9x2-48=18x equation:

9x^2-48=18x

We move all terms to the left:

9x^2-48-(18x)=0

a = 9; b = -18; c = -48;
Δ = b2-4ac
Δ = -182-4·9·(-48)
Δ = 2052
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2052}=\sqrt{36*57}=\sqrt{36}*\sqrt{57}=6\sqrt{57}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-6\sqrt{57}}{2*9}=\frac{18-6\sqrt{57}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+6\sqrt{57}}{2*9}=\frac{18+6\sqrt{57}}{18}
$