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9x^2-155x-50=0
a = 9; b = -155; c = -50;
Δ = b2-4ac
Δ = -1552-4·9·(-50)
Δ = 25825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{25825}=\sqrt{25*1033}=\sqrt{25}*\sqrt{1033}=5\sqrt{1033}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-155)-5\sqrt{1033}}{2*9}=\frac{155-5\sqrt{1033}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-155)+5\sqrt{1033}}{2*9}=\frac{155+5\sqrt{1033}}{18} $
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