9x2-147=0

Solution for 9x2-147=0 equation:

9x^2-147=0

a = 9; b = 0; c = -147;
Δ = b2-4ac
Δ = 02-4·9·(-147)
Δ = 5292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5292}=\sqrt{1764*3}=\sqrt{1764}*\sqrt{3}=42\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-42\sqrt{3}}{2*9}=\frac{0-42\sqrt{3}}{18}
=-\frac{42\sqrt{3}}{18}
=-\frac{7\sqrt{3}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+42\sqrt{3}}{2*9}=\frac{0+42\sqrt{3}}{18}
=\frac{42\sqrt{3}}{18}
=\frac{7\sqrt{3}}{3}
$