8z-(4z+10)=3(z-2)

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Solution for 8z-(4z+10)=3(z-2) equation: 



8z-(4z+10)=3(z-2)

We move all terms to the left:

8z-(4z+10)-(3(z-2))=0

We get rid of parentheses

8z-4z-(3(z-2))-10=0



We calculate terms in parentheses: -(3(z-2)), so:

3(z-2)

We multiply parentheses

3z-6

Back to the equation:

-(3z-6)



We add all the numbers together, and all the variables

4z-(3z-6)-10=0

We get rid of parentheses

4z-3z+6-10=0

We add all the numbers together, and all the variables

z-4=0

We move all terms containing z to the left, all other terms to the right

z=4

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