9x-x=7(x-10)-(2x-2)

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Solution for 9x-x=7(x-10)-(2x-2) equation: 



9x-x=7(x-10)-(2x-2)

We move all terms to the left:

9x-x-(7(x-10)-(2x-2))=0

We add all the numbers together, and all the variables

8x-(7(x-10)-(2x-2))=0



We calculate terms in parentheses: -(7(x-10)-(2x-2)), so:

7(x-10)-(2x-2)

We multiply parentheses

7x-(2x-2)-70

We get rid of parentheses

7x-2x+2-70

We add all the numbers together, and all the variables

5x-68

Back to the equation:

-(5x-68)



We get rid of parentheses

8x-5x+68=0

We add all the numbers together, and all the variables

3x+68=0

We move all terms containing x to the left, all other terms to the right

3x=-68

x=-68/3

x=-22+2/3

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