4(x-3)-(2x+6)=4(x-3)+2x-4

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Solution for 4(x-3)-(2x+6)=4(x-3)+2x-4 equation: 



4(x-3)-(2x+6)=4(x-3)+2x-4

We move all terms to the left:

4(x-3)-(2x+6)-(4(x-3)+2x-4)=0

We multiply parentheses

4x-(2x+6)-(4(x-3)+2x-4)-12=0

We get rid of parentheses

4x-2x-(4(x-3)+2x-4)-6-12=0



We calculate terms in parentheses: -(4(x-3)+2x-4), so:

4(x-3)+2x-4

We add all the numbers together, and all the variables

2x+4(x-3)-4

We multiply parentheses

2x+4x-12-4

We add all the numbers together, and all the variables

6x-16

Back to the equation:

-(6x-16)



We add all the numbers together, and all the variables

2x-(6x-16)-18=0

We get rid of parentheses

2x-6x+16-18=0

We add all the numbers together, and all the variables

-4x-2=0

We move all terms containing x to the left, all other terms to the right

-4x=2

x=2/-4

x=-1/2

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