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9x-7/3x+5=3x-4/x+6
We move all terms to the left:
9x-7/3x+5-(3x-4/x+6)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: x+6)!=0We get rid of parentheses
x∈R
9x-7/3x-3x+4/x-6+5=0
We calculate fractions
9x-3x+(-7x)/3x^2+12x/3x^2-6+5=0
We add all the numbers together, and all the variables
6x+(-7x)/3x^2+12x/3x^2-1=0
We multiply all the terms by the denominator
6x*3x^2+(-7x)+12x-1*3x^2=0
We add all the numbers together, and all the variables
12x+6x*3x^2+(-7x)-1*3x^2=0
Wy multiply elements
18x^3-3x^2+12x+(-7x)=0
We get rid of parentheses
18x^3-3x^2+12x-7x=0
We do not support expression: x^3
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