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1/3(x+2)+5/6(x-1)=x-3
We move all terms to the left:
1/3(x+2)+5/6(x-1)-(x-3)=0
Domain of the equation: 3(x+2)!=0
x∈R
Domain of the equation: 6(x-1)!=0We get rid of parentheses
x∈R
1/3(x+2)+5/6(x-1)-x+3=0
We calculate fractions
-x+(6xx/(3(x+2)*6(x-1))+(15xx/(3(x+2)*6(x-1))+3=0
We can not solve this equation
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