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9x-10/12x=0
Domain of the equation: 12x!=0We multiply all the terms by the denominator
x!=0/12
x!=0
x∈R
9x*12x-10=0
Wy multiply elements
108x^2-10=0
a = 108; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·108·(-10)
Δ = 4320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4320}=\sqrt{144*30}=\sqrt{144}*\sqrt{30}=12\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{30}}{2*108}=\frac{0-12\sqrt{30}}{216} =-\frac{12\sqrt{30}}{216} =-\frac{\sqrt{30}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{30}}{2*108}=\frac{0+12\sqrt{30}}{216} =\frac{12\sqrt{30}}{216} =\frac{\sqrt{30}}{18} $
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