21-3x=1/2x+1

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Solution for 21-3x=1/2x+1 equation:



21-3x=1/2x+1
We move all terms to the left:
21-3x-(1/2x+1)=0
Domain of the equation: 2x+1)!=0
x∈R
We get rid of parentheses
-3x-1/2x-1+21=0
We multiply all the terms by the denominator
-3x*2x-1*2x+21*2x-1=0
Wy multiply elements
-6x^2-2x+42x-1=0
We add all the numbers together, and all the variables
-6x^2+40x-1=0
a = -6; b = 40; c = -1;
Δ = b2-4ac
Δ = 402-4·(-6)·(-1)
Δ = 1576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1576}=\sqrt{4*394}=\sqrt{4}*\sqrt{394}=2\sqrt{394}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-2\sqrt{394}}{2*-6}=\frac{-40-2\sqrt{394}}{-12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+2\sqrt{394}}{2*-6}=\frac{-40+2\sqrt{394}}{-12} $

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