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(10x+3)+(12x-5)=90
We move all terms to the left:
(10x+3)+(12x-5)-(90)=0
We get rid of parentheses
10x+12x+3-5-90=0
We add all the numbers together, and all the variables
22x-92=0
We move all terms containing x to the left, all other terms to the right
22x=92
x=92/22
x=4+2/11
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