9x-(x-8)=2x-(4x+1)

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Solution for 9x-(x-8)=2x-(4x+1) equation: 



9x-(x-8)=2x-(4x+1)

We move all terms to the left:

9x-(x-8)-(2x-(4x+1))=0

We get rid of parentheses

9x-x-(2x-(4x+1))+8=0



We calculate terms in parentheses: -(2x-(4x+1)), so:

2x-(4x+1)

We get rid of parentheses

2x-4x-1

We add all the numbers together, and all the variables

-2x-1

Back to the equation:

-(-2x-1)



We add all the numbers together, and all the variables

8x-(-2x-1)+8=0

We get rid of parentheses

8x+2x+1+8=0

We add all the numbers together, and all the variables

10x+9=0

We move all terms containing x to the left, all other terms to the right

10x=-9

x=-9/10

x=-9/10

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