2(4z+4)=4(3z+6)

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Solution for 2(4z+4)=4(3z+6) equation: 



2(4z+4)=4(3z+6)

We move all terms to the left:

2(4z+4)-(4(3z+6))=0

We multiply parentheses

8z-(4(3z+6))+8=0



We calculate terms in parentheses: -(4(3z+6)), so:

4(3z+6)

We multiply parentheses

12z+24

Back to the equation:

-(12z+24)



We get rid of parentheses

8z-12z-24+8=0

We add all the numbers together, and all the variables

-4z-16=0

We move all terms containing z to the left, all other terms to the right

-4z=16

z=16/-4

z=-4

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