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4x-1=3(x+1)-(4-x)
We move all terms to the left:
4x-1-(3(x+1)-(4-x))=0
We add all the numbers together, and all the variables
4x-(3(x+1)-(-1x+4))-1=0
We calculate terms in parentheses: -(3(x+1)-(-1x+4)), so:We get rid of parentheses
3(x+1)-(-1x+4)
We multiply parentheses
3x-(-1x+4)+3
We get rid of parentheses
3x+1x-4+3
We add all the numbers together, and all the variables
4x-1
Back to the equation:
-(4x-1)
4x-4x+1-1=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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