9x-(2x+5+x2)-7(x+5)=-x2+5x-(3x-8)

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Solution for 9x-(2x+5+x2)-7(x+5)=-x2+5x-(3x-8) equation: 



9x-(2x+5+x2)-7(x+5)=-x2+5x-(3x-8)

We move all terms to the left:

9x-(2x+5+x2)-7(x+5)-(-x2+5x-(3x-8))=0

We add all the numbers together, and all the variables

-(+2x+x^2+5)+9x-7(x+5)-(-x2+5x-(3x-8))=0

We multiply parentheses

-(+2x+x^2+5)+9x-7x-(-x2+5x-(3x-8))-35=0

We get rid of parentheses

-x^2-2x+9x-7x-(-x2+5x-(3x-8))-5-35=0



We calculate terms in parentheses: -(-x2+5x-(3x-8)), so:

-x2+5x-(3x-8)

We add all the numbers together, and all the variables

-1x^2+5x-(3x-8)

We get rid of parentheses

-1x^2+5x-3x+8

We add all the numbers together, and all the variables

-1x^2+2x+8

Back to the equation:

-(-1x^2+2x+8)



We add all the numbers together, and all the variables

-1x^2-(-1x^2+2x+8)-40=0

We get rid of parentheses

-1x^2+1x^2-2x-8-40=0

We add all the numbers together, and all the variables

-2x-48=0

We move all terms containing x to the left, all other terms to the right

-2x=48

x=48/-2

x=-24

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