3(2x+1)=3(x+3)

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Solution for 3(2x+1)=3(x+3) equation: 



3(2x+1)=3(x+3)

We move all terms to the left:

3(2x+1)-(3(x+3))=0

We multiply parentheses

6x-(3(x+3))+3=0



We calculate terms in parentheses: -(3(x+3)), so:

3(x+3)

We multiply parentheses

3x+9

Back to the equation:

-(3x+9)



We get rid of parentheses

6x-3x-9+3=0

We add all the numbers together, and all the variables

3x-6=0

We move all terms containing x to the left, all other terms to the right

3x=6

x=6/3

x=2

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