9x+9(3-2x)=12(3-x)

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Solution for 9x+9(3-2x)=12(3-x) equation: 



9x+9(3-2x)=12(3-x)

We move all terms to the left:

9x+9(3-2x)-(12(3-x))=0

We add all the numbers together, and all the variables

9x+9(-2x+3)-(12(-1x+3))=0

We multiply parentheses

9x-18x-(12(-1x+3))+27=0



We calculate terms in parentheses: -(12(-1x+3)), so:

12(-1x+3)

We multiply parentheses

-12x+36

Back to the equation:

-(-12x+36)



We add all the numbers together, and all the variables

-9x-(-12x+36)+27=0

We get rid of parentheses

-9x+12x-36+27=0

We add all the numbers together, and all the variables

3x-9=0

We move all terms containing x to the left, all other terms to the right

3x=9

x=9/3

x=3

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