4(2h+1)-2(h+3)=2(h-3)-4

Solution for 4(2h+1)-2(h+3)=2(h-3)-4 equation:

4(2h+1)-2(h+3)=2(h-3)-4

We move all terms to the left:

4(2h+1)-2(h+3)-(2(h-3)-4)=0

We multiply parentheses

8h-2h-(2(h-3)-4)+4-6=0


We calculate terms in parentheses: -(2(h-3)-4), so:

2(h-3)-4

We multiply parentheses

2h-6-4

We add all the numbers together, and all the variables

2h-10

Back to the equation:

-(2h-10)


We add all the numbers together, and all the variables

6h-(2h-10)-2=0

We get rid of parentheses

6h-2h+10-2=0

We add all the numbers together, and all the variables

4h+8=0

We move all terms containing h to the left, all other terms to the right

4h=-8

h=-8/4

h=-2